The circuit above is used to control DC Motor. IC MC33486 is capable of measuring the current of the motor (to build a servo control loop) and my question is How can it do that?
The datasheet of the IC give some brief information on my question, such as "
This feature provides a current mirror with the ratio of 1/3700 of the sum of the high-side output current. An external resistor must be connected to the Cur R terminal, then tied to a microcontroller A / D input for analog voltage measurement
This current recopy uses the well-known Wheatstone bridge principle with the Sense, the Power, and the load as the three known resistances.Owing to the internal zener clamp in the gate of the M1 transistor, the Cur R max voltage is typically 11 V."
"In case a ground shift occurs between the MCU and the 33486A, the amplifier A (Figure 6, page 10) will adapt its output to keep the same ICOPY. Of course the shift has to keep between ±1.0 V. "
but what does the bold sentence mean? could you help me to explain it?
Thanks in advance!