I found these linear regulators that can tolerate an input voltage of up to 700V (450V operating) and provide 10 ma of output current. Since package thermal resistance is 79 degrees C per watt, I'm uncertain how the device can provide 10 ma of output current. Assuming 450V input voltage and the 15V output version, that means 4.35 watts dissipated by the regulator at 10 ma output. Based on the 85 C max operating temperature (though shutdown doesn't occur until 145 C) and 20 C ambient, allowing temperature rise is only 65 C which corresponds to 0.82 watts power dissipation. That implies a maximum output current of only 1.9 ma continuously. I've never worked with regulators with this high an input voltage, but can't think of why a high voltage linear regulator would work difference than a low voltage one. Am I missing something?
https://www.onsemi.com/PowerSolutions/parametrics/366/productsPosted on: July 25, 2019, 07:58:06 19:58 - Automerged
It occurred to me a high input voltage switching power supply wouldn't be much different than one designed for 230/240 VAC input (like utility line voltage in most of the world other than the US, Mexico, and Japan). 240VAC rectified is 340V which is pretty close to what I need. And most small switching power supplies are designed to work with 100-240VAC input to cover the whole world. (Japan has the oddball 100 VAC line voltage, except on US military bases where it is 120VAC.) So, I wonder how low the input voltage can drop before the typical switching power supply loses regulation. I can't think of why a typical SPS wouldn't accept DC input. The only problem I can think of is the undervoltage protection in some designs. I guess I'll try running some small switching from a DC power supply and see how they behave as the voltage drops before the mininum rated operating voltage.